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    高二年級(jí)化學(xué)上冊方程式總結(jié)

    時(shí)間:2018-08-22 14:11:00   來源:無憂考網(wǎng)     [字體: ]
    【#高二# #高二年級(jí)化學(xué)上冊方程式總結(jié)#】如果把高中三年去挑戰(zhàn)高考看作一次越野長跑的話,那么高中二年級(jí)是這個(gè)長跑的中段。與起點(diǎn)相比,它少了許多的鼓勵(lì)、期待,與終點(diǎn)相比,它少了許多的掌聲、加油聲。它是孤身奮斗的階段,是一個(gè)耐力、意志、自控力比拚的階段。但它同時(shí)是一個(gè)厚實(shí)莊重的階段,這個(gè)時(shí)期形成的優(yōu)勢有實(shí)力。©無憂考網(wǎng)高二頻道為你整理了《高二年級(jí)化學(xué)上冊方程式總結(jié)》,學(xué)習(xí)路上,©無憂考網(wǎng)為你加油!

      非金屬單質(zhì)(F2,Cl2,O2,S,N2,P,C,Si)

      1,氧化性:

      F2+H2===2HF

      F2+Xe(過量)===XeF2

      2F2(過量)+Xe===XeF4

      nF2+2M===2MFn(表示大部分金屬)

      2F2+2H2O===4HF+O2

      2F2+2NaOH===2NaF+OF2+H2O

      F2+2NaCl===2NaF+Cl2

      F2+2NaBr===2NaF+Br2

      F2+2NaI===2NaF+I2

      F2+Cl2(等體積)===2ClF

      3F2(過量)+Cl2===2ClF3

      7F2(過量)+I2===2IF7

      Cl2+H2===2HCl

      3Cl2+2P===2PCl3

      Cl2+PCl3===PCl5

      Cl2+2Na===2NaCl

      3Cl2+2Fe===2FeCl3

      Cl2+2FeCl2===2FeCl3

      Cl2+Cu===CuCl2

      2Cl2+2NaBr===2NaCl+Br2

      Cl2+2NaI===2NaCl+I2

      5Cl2+I2+6H2O===2HIO3+10HCl

      Cl2+Na2S===2NaCl+S

      Cl2+H2S===2HCl+S

      Cl2+SO2+2H2O===H2SO4+2HCl

      Cl2+H2O2===2HCl+O2

      2O2+3Fe===Fe3O4

      O2+K===KO2

      S+H2===H2S

      2S+C===CS2

      S+Fe===FeS

      S+2Cu===Cu2S

      3S+2Al===Al2S3

      S+Zn===ZnS

      N2+3H2===2NH3

      N2+3Mg===Mg3N2

      N2+3Ca===Ca3N2

      N2+3Ba===Ba3N2

      N2+6Na===2Na3N

      N2+6K===2K3N

      N2+6Rb===2Rb3N

      P2+6H2===4PH3

      P+3Na===Na3P

      2P+3Zn===Zn3P2

      2.還原性

      S+O2===SO2

      S+O2===SO2

      S+6HNO3(濃)===H2SO4+6NO2+2H2O

      3S+4HNO3(稀)===3SO2+4NO+2H2O

      N2+O2===2NO

      4P+5O2===P4O10(常寫成P2O5)

      2P+3X2===2PX3(X表示F2,Cl2,Br2)

      PX3+X2===PX5

      P4+20HNO3(濃)===4H3PO4+20NO2+4H2O

      C+2F2===CF4

      C+2Cl2===CCl4

      2C+O2(少量)===2CO

      C+O2(足量)===CO2

      C+CO2===2CO

      C+H2O===CO+H2(生成水煤氣)

      2C+SiO2===Si+2CO(制得粗硅)

      Si(粗)+2Cl===SiCl4

      (SiCl4+2H2===Si(純)+4HCl)

      Si(粉)+O2===SiO2

      Si+C===SiC(金剛砂)

      Si+2NaOH+H2O===Na2SiO3+2H2

      3,(堿中)歧化

      Cl2+H2O===HCl+HClO

     。铀嵋种破缁,加堿或光照促進(jìn)歧化)

      Cl2+2NaOH===NaCl+NaClO+H2O

      2Cl2+2Ca(OH)2===CaCl2+Ca(ClO)2+2H2O

      3Cl2+6KOH(熱,濃)===5KCl+KClO3+3H2O

      3S+6NaOH===2Na2S+Na2SO3+3H2O

      4P+3KOH(濃)+3H2O===PH3+3KH2PO2

      11P+15CuSO4+24H2O===5Cu3P+6H3PO4+15H2SO4

      3C+CaO===CaC2+CO

      3C+SiO2===SiC+2CO

      二,金屬單質(zhì)(Na,Mg,Al,Fe)的還原性

      2Na+H2===2NaH

      4Na+O2===2Na2O

      2Na2O+O2===2Na2O2

      2Na+O2===Na2O2

      2Na+S===Na2S(爆炸)

      2Na+2H2O===2NaOH+H2

      2Na+2NH3===2NaNH2+H2

      4Na+TiCl4(熔融)===4NaCl+Ti

      Mg+Cl2===MgCl2

      Mg+Br2===MgBr2

      2Mg+O2===2MgO

      Mg+S===MgS

      Mg+2H2O===Mg(OH)2+H2

      2Mg+TiCl4(熔融)===Ti+2MgCl2

      Mg+2RbCl===MgCl2+2Rb

      2Mg+CO2===2MgO+C

      2Mg+SiO2===2MgO+Si

      Mg+H2S===MgS+H2

      Mg+H2SO4===MgSO4+H2

      2Al+3Cl2===2AlCl3

      4Al+3O2===2Al2O3(鈍化)

      4Al(Hg)+3O2+2xH2O===2(Al2O3.xH2O)+4Hg

      4Al+3MnO2===2Al2O3+3Mn

      2Al+Cr2O3===Al2O3+2Cr

      2Al+Fe2O3===Al2O3+2Fe

      2Al+3FeO===Al2O3+3Fe

      2Al+6HCl===2AlCl3+3H2

      2Al+3H2SO4===Al2(SO4)3+3H2

      2Al+6H2SO4(濃)===Al2(SO4)3+3SO2+6H2O

      (Al,Fe在冷,濃的H2SO4,HNO3中鈍化)

      Al+4HNO(稀)===Al(NO3)3+NO+2H2O

      2Al+2NaOH+2H2O===2NaAlO2+3H2

      2Fe+3Br2===2FeBr3

      Fe+I2===FeI2

      Fe+S===FeS

      3Fe+4H2O(g)===Fe3O4+4H2

      Fe+2HCl===FeCl2+H2

      Fe+CuCl2===FeCl2+Cu

      Fe+SnCl4===FeCl2+SnCl2

      (鐵在酸性環(huán)境下,不能把四氯化錫完全

      還原為單質(zhì)錫Fe+SnCl2==FeCl2+Sn)

      三,非金屬氫化物(HF,HCl,H2O,H2S,NH3)

      1,還原性:

      4HCl(濃)+MnO2===MnCl2+Cl2+2H2O

      4HCl(g)+O2===2Cl2+2H2O

      16HCl+2KMnO4===2KCl+2MnCl2+5Cl2+8H2O

      14HCl+K2Cr2O7===2KCl+2CrCl3+3Cl2+7H2O

      2H2O+2F2===4HF+O2

      2H2S+3O2(足量)===2SO2+2H2O

      2H2S+O2(少量)===2S+2H2O

      2H2S+SO2===3S+2H2O

      H2S+H2SO4(濃)===S+SO2+2H2O

      3H2S+2HNO(稀)===3S+2NO+4H2O

      5H2S+2KMnO4+3H2SO4===2MnSO4+K2SO4+5S+8H2O

      3H2S+K2Cr2O7+4H2SO4===Cr2(SO4)3+K2SO4+3S+7H2O

      H2S+4Na2O2+2H2O===Na2SO4+6NaOH

      2NH3+3CuO===3Cu+N2+3H2O

      2NH3+3Cl2===N2+6HCl

      8NH3+3Cl2===N2+6NH4Cl

      4NH3+3O2(純氧)===2N2+6H2O

      4NH3+5O2===4NO+6H2O

      4NH3+6NO===5N2+6HO(用氨清除NO)

      NaH+H2O===NaOH+H2

      4NaH+TiCl4===Ti+4NaCl+2H2

      CaH2+2H2O===Ca(OH)2+2H2

      2,酸性:

      4HF+SiO2===SiF4+2H2O

     。ù朔磻(yīng)廣泛應(yīng)用于測定礦樣或鋼樣中SiO2的含量)

      2HF+CaCl2===CaF2+2HCl

      H2S+Fe===FeS+H2

      H2S+CuCl2===CuS+2HCl

      H2S+2AgNO3===Ag2S+2HNO3

      H2S+HgCl2===HgS+2HCl

      H2S+Pb(NO3)2===PbS+2HNO3

      H2S+FeCl2===

      2NH3+2Na==2NaNH2+H2

      (NaNH2+H2O===NaOH+NH3)

      3,堿性:

      NH3+HCl===NH4Cl

      NH3+HNO3===NH4NO3

      2NH3+H2SO4===(NH4)2SO4

      NH3+NaCl+H2O+CO2===NaHCO3+NH4Cl

     。ù朔磻(yīng)用于工業(yè)制備小蘇打,蘇打)

      4,不穩(wěn)定性:

      2HF===H2+F2

      2HCl===H2+Cl2

      2H2O===2H2+O2

      2H2O2===2H2O+O2

      H2S===H2+S

      2NH3===N2+3H2

      四,非金屬氧化物

      低價(jià)態(tài)的還原性:

      2SO2+O2===2SO3

      2SO2+O2+2H2O===2H2SO4

     。ㄟ@是SO2在大氣中緩慢發(fā)生的環(huán)境化學(xué)反應(yīng))

      SO2+Cl2+2H2O===H2SO4+2HCl

      SO2+Br2+2H2O===H2SO4+2HBr

      SO2+I2+2H2O===H2SO4+2HI

      SO2+NO2===SO3+NO

      2NO+O2===2NO2

      NO+NO2+2NaOH===2NaNO2

     。ㄓ糜谥*工業(yè)中吸收尾氣中的NO和NO2)

      2CO+O2===2CO2

      CO+CuO===Cu+CO2

      3CO+Fe2O3===2Fe+3CO2

      CO+H2O===CO2+H2

      氧化性:

      SO2+2H2S===3S+2H2O

      SO3+2KI===K2SO3+I2

      NO2+2KI+H2O===NO+I2+2KOH

     。ú荒苡玫矸跭I溶液鑒別溴蒸氣和NO2)

      4NO2+H2S===4NO+SO3+H2O

      2NO2+Cu===4CuO+N2

      CO2+2Mg===2MgO+C

      (CO2不能用于撲滅由Mg,Ca,Ba,Na,K等燃燒的火災(zāi))

      SiO2+2H2===Si+2H2O

      SiO2+2Mg===2MgO+Si

      3,與水的作用:

      SO2+H2O===H2SO3

      SO3+H2O===H2SO4

      3NO2+H2O===2HNO3+NO

      N2O5+H2O===2HNO3

      P2O5+H2O===2HPO3

      P2O5+3H2O===2H3PO4

      (P2O5極易吸水,可作氣體干燥劑

      P2O5+3H2SO4(濃)===2H3PO4+3SO3)

      CO2+H2O===H2CO3

      4,與堿性物質(zhì)的作用:

      SO2+2NH3+H2O===(NH4)2SO3

      SO2+(NH4)2SO3+H2O===2NH4HSO3

      (這是硫酸廠回收SO2的反應(yīng).先用氨水吸收SO2,

      再用H2SO4處理:2NH4HSO3+H2SO4===(NH4)2SO4+2H2O+2SO2

      生成的硫酸銨作化肥,SO2循環(huán)作原料氣)

      SO2+Ca(OH)2===CaSO3+H2O

      (不能用澄清石灰水鑒別SO2和CO2.可用品紅鑒別)

      SO3+MgO===MgSO4

      SO3+Ca(OH)2===CaSO4+H2O

      CO2+2NaOH(過量)===Na2CO3+H2O

      CO2(過量)+NaOH===NaHCO3

      CO2+Ca(OH)2(過量)===CaCO3+H2O

      2CO2(過量)+Ca(OH)2===Ca(HCO3)2

      CO2+2NaAlO2+3H2O===2Al(OH)3+Na2CO3

      CO2+C6H5ONa+H2O===C6H5OH+NaHCO3

      SiO2+CaO===CaSiO3

      SiO2+2NaOH===Na2SiO3+H2O

      (常溫下強(qiáng)堿緩慢腐蝕玻璃)

      SiO2+Na2CO3===Na2SiO3+CO2

      SiO2+CaCO3===CaSiO3+CO2

      五,金屬氧化物

      1,低價(jià)態(tài)的還原性:

      6FeO+O2===2Fe3O4

      FeO+4HNO3===Fe(NO3)3+NO2+2H2O

      2,氧化性:

      Na2O2+2Na===2Na2O

      (此反應(yīng)用于制備Na2O)

      MgO,Al2O3幾乎沒有氧化性,很難被還原為Mg,Al.

      一般通過電解制Mg和Al.

      Fe2O3+3H2===2Fe+3H2O(制還原鐵粉)

      Fe3O4+4H2===3Fe+4H2O

      3,與水的作用:

      Na2O+H2O===2NaOH

      2Na2O2+2H2O===4NaOH+O2

      (此反應(yīng)分兩步:Na2O2+2H2O===2NaOH+H2O2;

      2H2O2===2H2O+O2.H2O2的制備可利用類似的反應(yīng):

      BaO2+H2SO4(稀)===BaSO4+H2O2)

      MgO+H2O===Mg(OH)2(緩慢反應(yīng))

      4,與酸性物質(zhì)的作用:

      Na2O+SO3===Na2SO4

      Na2O+CO2===Na2CO3

      Na2O+2HCl===2NaCl+H2O

      2Na2O2+2CO2===2Na2CO3+O2

      Na2O2+H2SO4(冷,稀)===Na2SO4+H2O2

      MgO+SO3===MgSO4

      MgO+H2SO4===MgSO4+H2O

      Al2O3+3H2SO4===Al2(SO4)3+3H2O

      (Al2O3是*氧化物:

      Al2O3+2NaOH===2NaAlO2+H2O)

      FeO+2HCl===FeCl2+3H2O

      Fe2O3+6HCl===2FeCl3+3H2O

      Fe2O3+3H2S(g)===Fe2S3+3H2O

      Fe3O4+8HCl===FeCl2+2FeCl3+4H2O

      六,含氧酸

      1,氧化性:

      4HClO3+3H2S===3H2SO4+4HCl

      HClO3+HI===HIO3+HCl

      3HClO+HI===HIO3+3HCl

      HClO+H2SO3===H2SO4+HCl

      HClO+H2O2===HCl+H2O+O2

      (氧化性:HClO>HClO2>HClO3>HClO4,

      但濃,熱的HClO4氧化性很強(qiáng))

      2H2SO4(濃)+C===CO2+2SO2+2H2O

      2H2SO4(濃)+S===3SO2+2H2O

      H2SO4+Fe(Al)室溫下鈍化

      6H2SO4(濃)+2Fe===Fe2(SO4)3+3SO2+6H2O

      2H2SO4(濃)+Cu===CuSO4+SO2+2H2O

      H2SO4(濃)+2HBr===SO2+Br2+2H2O

      H2SO4(濃)+2HI===SO2+I2+2H2O

      H2SO4(稀)+Fe===FeSO4+H2

      2H2SO3+2H2S===3S+2H2O

      4HNO3(濃)+C===CO2+4NO2+2H2O

      6HNO3(濃)+S===H2SO4+6NO2+2H2O

      5HNO3(濃)+P===H3PO4+5NO2+H2O

      6HNO3+Fe===Fe(NO3)3+3NO2+3H2O

      4HNO3+Fe===Fe(NO3)3+NO+2H2O

      30HNO3+8Fe===8Fe(NO3)3+3N2O+15H2O

      36HNO3+10Fe===10Fe(NO3)3+3N2+18H2O

      30HNO3+8Fe===8Fe(NO3)3+3NH4NO3+9H2O

      2,還原性:

      H2SO3+X2+H2O===H2SO4+2HX

      (X表示Cl2,Br2,I2)

      2H2SO3+O2===2H2SO4

      H2SO3+H2O2===H2SO4+H2O

      5H2SO3+2KMnO4===2MnSO4+K2SO4+2H2SO4+3H2O

      H2SO3+2FeCl3+H2O===H2SO4+2FeCl2+2HCl

      3,酸性:

      H2SO4(濃)+CaF2===CaSO4+2HF

      H2SO4(濃)+NaCl===NaHSO4+HCl

      H2SO4(濃)+2NaCl===Na2SO4+2HCl

      H2SO4(濃)+NaNO3===NaHSO4+HNO3

      3H2SO4(濃)+Ca3(PO4)2===3CaSO4+2H3PO4

      2H2SO4(濃)+Ca3(PO4)2===2CaSO4+Ca(H2PO4)2

      3HNO3+Ag3PO4===H3PO4+3AgNO3

      2HNO3+CaCO3===Ca(NO3)2+H2O+CO2

     。ㄓ肏NO3和濃H2SO4不能制備H2S,HI,HBr,(SO2)

      等還原性氣體)

      4H3PO4+Ca3(PO4)2===3Ca(H2PO4)2(重鈣)

      H3PO4(濃)+NaBr===NaH2PO4+HBr

      H3PO4(濃)+NaI===NaH2PO4+HI

      4,不穩(wěn)定性:

      2HClO===2HCl+O2

      4HNO3===4NO2+O2+2H2O

      H2SO3===H2O+SO2

      H2CO3===H2O+CO2

      H4SiO4===H2SiO3+H2O

      七,堿

      低價(jià)態(tài)的還原性:

      4Fe(OH)2+O2+2H2O===4Fe(OH)3

      與酸性物質(zhì)的作用:

      2NaOH+SO2(少量)===Na2SO3+H2O

      NaOH+SO2(足量)===NaHSO3

      2NaOH+SiO2===NaSiO3+H2O

      2NaOH+Al2O3===2NaAlO2+H2O

      2NaOH+Cl2===NaCl+NaClO+H2O

      NaOH+HCl===NaCl+H2O

      NaOH+H2S(足量)===NaHS+H2O

      2NaOH+H2S(少量)===Na2S+2H2O

      3NaOH+AlCl3===Al(OH)3+3NaCl

      NaOH+Al(OH)3===NaAlO2+2H2O

      (AlCl3和Al(OH)3哪個(gè)酸性強(qiáng)?)

      NaOH+NH4Cl===NaCl+NH3+H2O

      Mg(OH)2+2NH4Cl===MgCl2+2NH3.H2O

      Al(OH)3+NH4Cl不溶解

      3,不穩(wěn)定性:

      Mg(OH)2===MgO+H2O

      2Al(OH)3===Al2O3+3H2O

      2Fe(OH)3===Fe2O3+3H2O

      Cu(OH)2===CuO+H2O

      八,鹽

      1,氧化性:

      2FeCl3+Fe===3FeCl2

      2FeCl3+Cu===2FeCl2+CuCl2

      (用于雕刻銅線路版)

      2FeCl3+Zn===2FeCl2+ZnCl2

      FeCl3+Ag===FeCl2+AgC

      Fe2(SO4)3+2Ag===FeSO4+Ag2SO4(較難反應(yīng))

      Fe(NO3)3+Ag不反應(yīng)

      2FeCl3+H2S===2FeCl2+2HCl+S

      2FeCl3+2KI===2FeCl2+2KCl+I2

      FeCl2+Mg===Fe+MgCl2

      2,還原性:

      2FeCl2+Cl2===2FeCl3

      3Na2S+8HNO3(稀)===6NaNO3+2NO+3S+4H2O

      3Na2SO3+2HNO3(稀)===3Na2SO4+2NO+H2O

      2Na2SO3+O2===2Na2SO4

      3,與堿性物質(zhì)的作用:

      MgCl2+2NH3.H2O===Mg(OH)2+NH4Cl

      AlCl3+3NH3.H2O===Al(OH)3+3NH4Cl

      FeCl3+3NH3.H2O===Fe(OH)3+3NH4Cl

      4,與酸性物質(zhì)的作用:

      Na3PO4+HCl===Na2HPO4+NaCl

      Na2HPO4+HCl===NaH2PO4+NaCl

      NaH2PO4+HCl===H3PO4+NaCl

      Na2CO3+HCl===NaHCO3+NaCl

      NaHCO3+HCl===NaCl+H2O+CO2

      3Na2CO3+2AlCl3+3H2O===2Al(OH)3+3CO2+6NaCl

      3Na2CO3+2FeCl3+3H2O===2Fe(OH)3+3CO2+6NaCl

      3NaHCO3+AlCl3===Al(OH)3+3CO2

      3NaHCO3+FeCl3===Fe(OH)3+3CO2

      3Na2S+Al2(SO4)3+6H2O===2Al(OH)3+3H2S

      3NaAlO2+AlCl3+6H2O===4Al(OH)3

      5,不穩(wěn)定性:

      Na2S2O3+H2SO4===Na2SO4+S+SO2+H2O

      NH4Cl===NH3+HCl

      NH4HCO3===NH3+H2O+CO2

      2KNO3===2KNO2+O2

      2Cu(NO3)3===2CuO+4NO2+O2

      2KMnO4===K2MnO4+MnO2+O2

      2KClO3===2KCl+3O2

      2NaHCO3===Na2CO3+H2O+CO2

      Ca(HCO3)2===CaCO3+H2O+CO2

      CaCO3===CaO+CO2

      MgCO3===MgO+CO2

      CH3CH2OH→CH2=CH2+H2O濃硫酸,170度

      CH2=CH2+Br2→CH2BrCH2Br

      CH2=CH2+H2O→CH3CH2OH催化劑

      CaC2+2H2O→CH≡CH↑+Ca(OH)2

      CH≡CH+Br2→CHBr=CHBr

      CH≡CH+HCl→CH2=CHCl催,加熱

      C6H6+Br2→C6H5Br+HBr催

      C6H6+HO-NO2→C6H6NO2+H2O濃硫酸,加熱

      C6H6+3H2→C6H12催,加熱

      C6H5-CH3+3HO-NO2→三硝基甲苯+3H2O濃硫酸,加熱

      C2H5Br+H2O→C2H5OH+HBrNaOH,加熱

      CH3CH2Br+NaOH→CH2=CH2↑+NaBr+H2O醇,加熱

      2CH3CH2OH+2Na→2CH3CH2ONa+H2↑

      2CH3CH2OH+O2→2CH3CHO+2H2O催,加熱

      C6H5OH+NaOH→C6H5ONa+H2O

      C6H5ONa+CO2+H2O→C6H5OH+NaHCO3

      C6H5OH+3Br2→三溴苯酚↓+3HBr

      CH3CHO+H2→CH3CH2OH催,加熱

      2CH3CHO+O2→2CH3COOH催,加熱

      CH3CHO+2Ag(NH3)2OH→H2O+2Ag↓+3NH3+CH3COONH4水浴加熱

      2CH3CHO+Cu(OH)2→2CH3COOH+Cu2O↓+H2O煮沸

      CH3COOH+C2H5OH→2CH3COOC2H5+H2O可逆,濃硫酸,加熱

      CH3COOC2H5+NaOH→CH3COONa+C2H5OH